Math, asked by gopaljikashyap4, 3 days ago

((√3+√2/√3-√2) +√3-√2)/√3+√2))​

Answers

Answered by sandy1816
1

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=(√3+√2/√3-√2) + (√3-√2/√3+√2)

=(√3+√2)²+(√3-√2)²/(√3)²-(√2)²

=2[(√3)²+(√2)²]/3-2

=2(3+2)

=10

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