((√3+√2/√3-√2) +√3-√2)/√3+√2))
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=(√3+√2/√3-√2) + (√3-√2/√3+√2)
=(√3+√2)²+(√3-√2)²/(√3)²-(√2)²
=2[(√3)²+(√2)²]/3-2
=2(3+2)
=10
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