Math, asked by anandajothi516, 4 months ago

(3^2)^3*(2*3^5)^-2*(18)^2 ​

Answers

Answered by Sankalp050
0

Answer:

 { {3}^{2} }^{3}  \times  {(2 \times  {3}^{5}) }^{ - 2}  \times  {18}^{2 }  \\  \\  =  {3}^{6}  \times  \frac{1}{4 \times  {3}^{10} }  \times  {18}^{2}  \\  \\  =  \frac{ {18}^{2} }{4 \times  {3}^{4} }  \\  \\  =  \frac{ \cancel{18 } \: ^{ \cancel{6}} \: ^{ \cancel{2}}\times { \cancel{18}}  \: ^{ \cancel{6 }} \:  ^{ \cancel{2}} \:  ^1 }{ { \cancel{4 }}\times { \cancel{3}} \times { \cancel{3 }}\times { \cancel{3}} \times { \cancel{3}} }  \\  \\  = { \huge{ \red{ \boxed{1}}}}

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