√3-√2 3+2
5.) Prove that the sum of
and
is a rational number.
√3+√2 13-12
1; +hodonam
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Answer:
Let us assume 3+2
5
+ is rational.
So we can write this number as
3+2
5
=
b
a
---- (1)
Here a and b are two co-prime number and b is not equal to zero.
Simplify the equation (1) subtract 3 both sides, we get
2
5
=
b
a
−3
2
5
=
b
a−3b
Now divide by 2 we get
5
=
2b
a−3b
Here a and b are integer so
2b
a−3b
is a rational number, so
5
should be a rational number.
But
5
is a irrational number, so it is contradict.
Therefore, 3+2
5
is irrational number.
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