Question

3+√2/ 3-√2 = a+b√2 then find a and b

Answer 1

Answer:$a=\frac{11}{7}$ and $b=\frac{6}{7}$

Step-by-step explanation:

$\frac{3+\sqrt{2}}{3-\sqrt{2}}=a+b\sqrt{2}$

Rationalising ,

$\frac{3+\sqrt{2} }{3-\sqrt{2}}$ $*$$\frac{3+\sqrt{2} }{3+\sqrt{2} }$$=\frac{(3+\sqrt{2})^2 }{3^2-(\sqrt{2)^2} }$$=\frac{9+2+6\sqrt{2} }{9-2}$$=\frac{11}{7} +(\frac{6}{7})\sqrt{2}$

On comparing we get

$a=\frac{11}{7}$ and $b=\frac{6}{7}$

Answer 2

Pls mark as brainliest answer