Question

√3+√2/√3-√2=a+b√6 find the answercplease​

Answer 1

Answer:

a = 5 and b = 2

Step-by-step explanation:

Given:-

• √3+√2/√3-√2=a+b√6

To find:-

• Values of a and b

Solution:-

√3+√2/√3-√2

⇒$\frac{\sqrt{3} +\sqrt{2} }{\sqrt{3} -\sqrt{2} }$ = $\frac{\sqrt{3} +\sqrt{2} }{\sqrt{3} -\sqrt{2} }$ × $\frac{\sqrt{3} +\sqrt{2} }{\sqrt{3} +\sqrt{2} }$

⇒$\frac{(\sqrt{3}+\sqrt{2})^{2} }{(\sqrt{3})^{2}- (\sqrt{2})^{2}}$ = $\frac{(\sqrt{3})^2+(\sqrt{2})^2+ 2(\sqrt{3})(\sqrt{2}) }{3-2}$

⇒$\frac{3+2+2\sqrt{6} }{1}$= 5 + 2√6

√3+√2/√3-√2 = a+b√6

⇒5 + 2√6 = a+b√6

⇒a = 5 and b = 2

Answer⇒ a = 5 and b = 2

I hope that this helped :-)