Math, asked by gurudevmahto546, 4 months ago

√3+√2÷√3-√2=a+b√6 find the value of a and b

Answers

Answered by vipashyana1
0

Answer:

a = 5 \: and \: b = 2

Step-by-step explanation:

 \frac{ \sqrt{3} +  \sqrt{2}  }{ \sqrt{3}  -  \sqrt{2} }  = a + b \sqrt{6}  \\  \frac{ \sqrt{3} +  \sqrt{2}  }{ \sqrt{3} -  \sqrt{2}  }  \times  \frac{ \sqrt{3} +  \sqrt{2}  }{ \sqrt{3}  +   \sqrt{2} } = a + b \sqrt{6}  \\  \frac{ {( \sqrt{3}  +  \sqrt{2} )}^{2} }{ {( \sqrt{3} )}^{2} -  {( \sqrt{2}) }^{2}  } = a + b \sqrt{6}  \\  \frac{3 + 2 +2  \sqrt{6} }{3 - 2} = a + b \sqrt{6}  \\  \frac{5 + 2 \sqrt{6} }{1} = a + b \sqrt{6}  \\ 5 + 2 \sqrt{6} = a + b \sqrt{6}  \\ a = 5 \: and \: b = 2

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