Question

(√3+√2)(√3-√2) is equal...(No Inappropriate Answers Or You Will Be Reported)

Answer 1

Hope it helps
Thank you

Answer 2

$\large\bf\underline\red{Answer \: :-}$

Using formula : (a+b) (a-b) = a² - b²

$\sf\longrightarrow{( \sqrt{3} + \sqrt{2})( \sqrt{3} - \sqrt{2} ) } \\ \\ \sf\longrightarrow{( \sqrt{3} ) {}^{2} - (\sqrt{2} ) {}^{2} } \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\\sf\longrightarrow{3 - 2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \bf\longrightarrow \red{1} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

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Learn more formula :

$\begin{gathered}\boxed{\begin{array}{c} \\ \tiny\bf{\dag}\:\underline{\frak{\rm{S}\frak{ome\:important\:algebric\:identities\:::}}} \\\\ \green{\bigstar}\:\rm \red{ (A+B)^{2} = A^{2} + 2AB + B^{2}} \\\\ \red{\bigstar}\rm\: \green{(A-B)^{2} = A^{2} - 2AB + B^{2}} \\\\ \orange{\bigstar}\rm\: \blue{A^{2} - B^{2} = (A+B)(A-B)}\\\\ \blue{\bigstar}\rm\: \orange{(A+B)^{2} = (A-B)^{2} + 4AB}\\\\ \pink{\bigstar}\rm\: \purple{(A-B)^{2} = (A+B)^{2} - 4AB}\\\\ \purple{\bigstar} \rm\: \pink{(A+B)^{3} = A^{3} + 3AB(A+B) + B^{3}}\\\\ \pink{\bigstar}\rm\:(A-B)^{3} = A^{3} - 3AB(A-B) - B^{3}\\\\ \bigstar\rm\: \red{A^{3} + B^{3} = (A+B)(A^{2} - AB + B^{2})} \\\\ \end{array}}\end{gathered}$