Question

3/2√3-3 rationalize denominator​

Answer 1

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Q:-

3/2√3-3 rationalize denominator

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$\frac{3}{2 \sqrt{3} - 3 } \times \frac{2 \sqrt{3} + 3 }{2 \sqrt{3} + 3 }$

$➾ \frac{3(2 \sqrt{3} + 3)}{ {(2 \sqrt{3}) }^{2} - {(3)}^{2} }$

$➾ \frac{3(2 \sqrt{3} + 3) }{12 - 9}$

$➾ \frac{3(2 \sqrt{3} + 3) }{3} = 2 \sqrt{3} + 3$✓

HOPE IT HELPS YOU..

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