Question

3^-2*3^-5 is equal to​

Answer 1

${3}^{ - 2} \times {3 }^{ - 5}$

Using exponent of law

${a}^{m} \times {a}^{n} = {a}^{m + n}$

Therefore

$= {3}^{ -2+ ( - 5)}$

$= {3}^{ - 7}$

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Answer 2

$\huge\underbrace\red{Answer}$

${3}^{ - 2} \times {3}^{ - 5} \\ \\ by \: using \: {a}^{m} \times {a}^{n} = {a}^{m + n} \\ \\ m = - 2 \\ n = - 5$

${3}^{ - 2} \times {3}^{ - 5} \\ {3}^{ - 2 + ( - 5)} \\ {3}^{ - 2 - 5} \\ {3}^{ - 7}$