(3+√2)(4+√3-√7) find the product
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Answered by
1
hey dear!
here is ur answer
....... .
(3+root2)(4+root3-root7)
=3 (4+r3-r7)+r2 (4+r3-r7)
=12+3r3-3r7+4r2+r6-r14
..
hope this will help you :)
here is ur answer
....... .
(3+root2)(4+root3-root7)
=3 (4+r3-r7)+r2 (4+r3-r7)
=12+3r3-3r7+4r2+r6-r14
..
hope this will help you :)
Answered by
2
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