Question

(3у2 + 5у — 4) — (8y - y2 - 4)​

Answer 1

Answer:

$( {3y}^{2} + 5y - 4) - (8y - {y}^{2} - 4) \\ solution \\ Given: \\ </p><p>(3y2+5y−4)−(8y−y2−4) \\ </p><p>=3y2+5y−4−8y+y2+4 \\ </p><p>=4y2−3y \\ </p><p>=y(4y−3). \\ </p><p></p><p>$

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Answer 2

Step-by-step explanation:

3y²+ 5y -4 - 8y + y² +4

3y² + y² + 5y - 8y - 4 + 4

therefore 4y²-3y=0