Math, asked by nandanidwivedi73, 4 months ago

3+2√5 prove that the rational and irrational number please jaldi se batao​

Answers

Answered by Anonymous
18

 \tt \huge \: Hola!

ProoF :

 \sf \large \: Let,

 \mapsto \sf \: 3+2√5 (=x) \:  \:  is \:  \:  a  \:  \: rational \:  \:  number \\

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \sf \: x = 3 + 2 \sqrt{5}

 \implies \sf \: 3 + x = 2 \sqrt{5}

 \implies \sf\frac{3 + x}{2}  =  \sqrt{5}  \\

 \sf  hence , \:  \: \sf \:rational \:  \: number \:  =  irrational \:  \: number \\

→ But it's not possible

hence,

 \sf  { \underline {\boxed{ \tt{ 3 - 2 \sqrt{5}  \:  \: is \:  \: a \:  \: irrational \:  \: number}}}}

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HOPE THIS IS HELPFUL...

Answered by aniket1573
0

Answer:

umake my friend please

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