Question

3√2÷√5
rationalise the denominator ​

Answer 1

Answer:

3root 10 upon 5

Step-by-step explanation:

3√2/√5×-√5/-√5=3√10/5

Answer 2

Answer:-

Your Answer Is $\bf\dfrac{3\sqrt{10}}{5}.$

Explanation:-

To Rationalise,

• The denominator of $\bf\dfrac{3\sqrt{2}}{\sqrt{5}}.$

Concepts Used:-

Suppose we have a fraction $\bf\dfrac{x}{y}.$

$\\ \tt \bigstar \: \: \: \dfrac{x}{y} \times \dfrac{y}{y} = \dfrac{x}{y} \times 1 = \dfrac{x}{y} .$

$\\ \boxed{\blue{\boxed{\red{\textrm{So We Can Say That \tt\dfrac{x}{y} can be written as \bf\dfrac{x}{y}\times\dfrac{y}{y} .}}}}}$

Rationalisation means??

• Rationalisation is the process of converting an irrational number to a rational numbet without changing its value.

• So here we have to rationalise the denominator this means we have to convert the denominator into a rational number.

So,

Lets Rationalise The Denominator:-

$\bf \mapsto \dfrac{3 \sqrt{2} }{ \sqrt{5} } . \: \: \: \: \: \: \: \: \: \: \ \\ \\ = \frac{3 \sqrt{2} }{ \sqrt{5} } \times \frac{ \sqrt{5} }{ \sqrt{5} } \\ \\ = \dfrac{ \sqrt{5}(3 \sqrt{2}) }{ \sqrt{5} \times \sqrt{5} }. \\ \\ = \frac{3 \sqrt{10} }{ \sqrt{25} } . \: \: \: \: \: \: \: \: \: \\ \\ \red{ \boxed{ \blue{\bf= \frac{3 \sqrt{10} }{5}.}}} \: \:$

Therefore Your Answer Is $\bf\dfrac{3\sqrt{10}}{5}.$