Math, asked by dritibatra, 8 months ago

3√2÷√5
rationalise the denominator ​

Answers

Answered by bhawesh379
0

Answer:

3root 10 upon 5

Step-by-step explanation:

3√2/√5×-√5/-√5=3√10/5

Answered by ItzAditt007
0

Answer:-

Your Answer Is \bf\dfrac{3\sqrt{10}}{5}.

Explanation:-

To Rationalise,

  • The denominator of \bf\dfrac{3\sqrt{2}}{\sqrt{5}}.

Concepts Used:-

Suppose we have a fraction \bf\dfrac{x}{y}.

 \\  \tt \bigstar \:  \:  \:  \dfrac{x}{y}  \times  \dfrac{y}{y}  =  \dfrac{x}{y}  \times 1 =  \dfrac{x}{y} .

\\ \boxed{\blue{\boxed{\red{\textrm{So We Can Say That $ \tt\dfrac{x}{y}$ can be written as  $ \bf\dfrac{x}{y}\times\dfrac{y}{y}$.}}}}}

Rationalisation means??

  • Rationalisation is the process of converting an irrational number to a rational numbet without changing its value.

  • So here we have to rationalise the denominator this means we have to convert the denominator into a rational number.

So,

Lets Rationalise The Denominator:-

 \bf \mapsto  \dfrac{3 \sqrt{2} }{ \sqrt{5} } . \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \ \\  \\  =   \frac{3 \sqrt{2} }{ \sqrt{5} }  \times   \frac{ \sqrt{5} }{ \sqrt{5} }  \\  \\  =   \dfrac{ \sqrt{5}(3 \sqrt{2})  }{ \sqrt{5} \times  \sqrt{5}  }.  \\  \\  =  \frac{3 \sqrt{10} }{ \sqrt{25} } .  \:  \:  \:  \:  \:  \:  \:  \:  \:   \\  \\     \red{ \boxed{ \blue{\bf=  \frac{3 \sqrt{10} }{5}.}}}  \:  \:

Therefore Your Answer Is \bf\dfrac{3\sqrt{10}}{5}.

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