Question

3(2+5x)/4= 2(6x-3)/5​

Answer 1

Answer:

in the middle is it-or =

Step-by-step explanation:

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Answer 2

Question

$\sf \large \dfrac{3(2 + 5x)}{4} = \dfrac{2(6x - 3)}{5}$

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

$\sf \longmapsto \large \dfrac{3(2 + 5x)}{4} = \dfrac{2(6x - 3)}{5}$

$\sf \longmapsto \dfrac{6 + 15x}{4} = \dfrac{12x - 6}{5}$

$\sf \longmapsto30 + 75x = 48x - 24$

$\sf \longmapsto75x - 48x = - 24 - 30$

$\sf \longmapsto27x = - 54$

$\sf \longmapsto \: x = \dfrac{ - 54}{27} = - 2$

$\sf\large\boxed{ \bold{ \red{x = - 2}}}$

Check:-

LHS

$\sf \longmapsto \dfrac{3(2 + 5x)}{4} = \dfrac{3(2 + 5( - 2))}{4} = \dfrac{3(2 - 10)}{4}$

$\sf \longmapsto \dfrac{3( - 8)}{4} = \dfrac{ - 24}{4} = - 6$

RHS

$\sf \longmapsto \dfrac{2(6x - 3)}{5} = \dfrac{2(6( - 2) - 3))}{5}$

$\sf \longmapsto \dfrac{2( - 12 - 3)}{5} = \dfrac{2( - 15)}{5} = \dfrac{ - 30}{5} = - 6$

Therefore,LHS=RHS (verified )