Question

(3,-2)and (6,-7) find midvalue​

Answer 1

Step-by-step explanation:

For x cordinate,

$\frac{3+6}{2} = [tex] 4\frac{1}{2}$

Answer 2

Answer:

Mid-value:-

$( \frac{3 + 6}{2} . \frac{ - 2 + ( - 7)}{2} )$

$= ( \frac{9}{2} and \frac{ - 9}{2} )$