Question

-3/2 and -6/8 which is greater​

Answer 1

Answer:

       $Given,\\\\\frac{-3}{2} And\frac{-6}{8} \\\\multiplying \: \:\: denominators \:\:\: with \:\:the\: fraction ,\\\\= \frac{-3*8}{2*8} \:\:and \: \:\frac{-6*2}{8*2} \\\\=\frac{-24}{16} \:\:and \: \: \frac{-12}{16} \\\\By \:\: comparing \:\: we \:\; get,\\\\\frac{-24}{16} \:\:< \: \: \frac{-12}{16} (Ans.) \\\\Hope \ it \ helps\\please\ mark \ as \ brainliest$

Answer 2

Answer:

-6/8

Step-by-step explanation:

-3/2 = -3÷2 = ‐1.5

-6/8 = -6÷8 = -0.75

-0.75 is near to 1

so the greatest is -0.75 = -6/8