Question

3-√2 is an irrational number prove​

Answer 1

Answer:

3-√2 is an irrational number

Step-by-step explanation:

let us assume that 3-√2 is a rational number

=>3-√2=p/q (q is not equal to 0 and p$q are coprime)

=> -√2=p/q-2

=> √2=2-p/q

=> √2=2q-p/q.....(1)

From eq. (1) we get that 2q-p/q and √2 is rational no.

But we know that √2 is an irrational no.

So contradiction arrise

Our assumption of √2 is a rational number is wrong

Therefore,

3-√2 is an irrational number (proved)