Question

3+2 log.3 = 2log (x+1)​

Answer 1

Answer:

3log10(2)−2log10(3)=1+log10(1x)3log10⁡(2)−2log10⁡(3)=1+log10⁡(1x)

⟹log10(23)−log10(32)=log10(10)+log10(1x)⟹log10⁡(23)−log10⁡(32)=log10⁡(10)+log10⁡(1x)

⟹log10(2332)=log10(10x)⟹log10⁡(2332)=log10⁡(10x)

⟹89=10x⟹89=10x

⟹x=454

Step-by-step explanation:

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Answer 2

3+2logx + 1³ = 2log ³x + 1

let's log 3 x + 1 = a

Therefore , 3 + ² = 2a

a

2a² - 3a - 2 = 0

2a² - 4a + a - 2 = 0

(2a+1) (a - 2) = 0

a = -1 , 2

2

Therefore,log3x + 1 = -¹ , log³x + 1 = 2 .

2

x + 1 = 1 , 9

√3

x = 1 - √3 , 8

√3