(3) 2 m/s, 4 m/s
A body moving with uniform acceleration is having
velocity 2 m/s and 8 m/s at t = 1 s and t = 4 s
respectively. Then average velocity of particle in the
time interval t = 1 s to t = 4 s is
(1) 2 m/s
(2) 3 m/s
(3) 5/3 m/s
(4) 5 m/s
Answers
Answered by
2
Explanation:
as velocity of particle vary linearly with time
V=u+at
av.vel=( ui-uf)/2
=(2+8)/2
=5m/s
Answered by
1
Answer:
Explanation:
a=(v-u) /t
where ,
a= acceleration
v=final velocity
u=initial velocity
t=time
So, the acceleration is (8–2)/(3–1)=2m/s^2
Now,
s= ut+1/2at^2
=(0*4+1/2*2*4^2)m [as the particle started from rest]
=(0+16)m
=16m
For the 1st second displacement was 1/2*2*1^2=1m
Now,
average velocity
=total displacement /total time
=(16–1/4–1)m/s
=5m/s
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