Question

3. 2 moles of a gas having y =7/5 is mixed with
1 mole of a gas having Y =5/3 The y for the

mixture will be
[NCERT Pg. 334)​

Answer 1

Answer:

Step-by-step explanation:

fmix=   $\frac{n1f1+n2f2}{n1+n2}$

gamma = $1+\frac{2}{7}$

         

Answer 2

Given :

Y for 3.2 moles gas = 7/5

Y for 1 mole gas = 5/3

Find:

The Y for the mixture of both the gases

Solution:

The Y mixture for two gases is given by the formula:

Y (mix) = (n1 * Cp1 + n2 * Cp2) / (n1 * Cv1 + n2 * Cv2)

here, n1 = number of moles of First gas = 3.2

        n2 = number of moles of Second gas = 1

        Cp1 = Specific heat at constant pressure for first gas

        Cp2 = Specific heat at constant pressure for second gas

        Cv1 = Specific heat at constant volume for first gas

        Cv2 = Specific heat at constant volume for second gas

Therefor by the formula

Cp1= Y * R / Y-1

Cp1 = 7/5 *R / (7/5) -1

Cp1 = 7R/2

Cv1 = Cp1 - R    (Cp - Cv = R)

Cv1 = 7R/2 - R = 5R/2

Cp2 = 5/3 *R / (5/3) -1

Cp2 = 5R/2

Cv2 = 5R/3 - R = 2R/3

using all the values in the formula we get :

          Y (mix) = (n1 * Cp1 + n2 * Cp2) / (n1 * Cv1 + n2 * Cv2)

          Y (mix) = (3.2 * 7R/2 + 1 * 5R/2) / ( 1 * 5R/2 + 3.2 * 2R/3)

           Y (mix) = 2.95

The Y for the mixture is 2.95.