Question

3.2 of a gas at stp occupies a volume of 2.24 l the gas is

Answer 1

Answer:

Sulphur

Explanation:

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Answer 2

The gas would be oxygen which occupies the volume of 2.24L at stp.

We have to identify a gas the mass of which is 3.2g at stp occupies a volume of 2.24 L.

It is not an easy task to identify a gas with just given data , because molecular mass of a gas may be same for more than one gases. There should be some options to find right answer.

Let's try to solve this question.

Given,

• mass of gas, w = 3.2 g
• volume of gas at STP , v = 2.24 L

We know, one mole of an ideal gas occupies a volume of 22.4 L at stp.

∵ 3.2 g of a gas occupies a volume of 2.24 L at stp.

∴ 32g of the same gas occupies a volume of 22.4 L at stp.

but gas occupies 22.4L at stp = one mole of gas

∴ one mole of gas = 32 g

∴ molecular mass of gas = 32 g/mol

Now, only one option comes in our mind and that is oxygen gas, isn't it ?

molecular mass of oxygen gas (O₂)  = 32 g/mol.

Therefore the gas would be oxygen which occupies the volume of 2.24L at stp.

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