Question

√3+√2 upon√3-√2 solve this the question is rationlise the denominator send photo of correct answer​

Answer 1

i hope this is helpful to you

Answer 2

Answer:

$\frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} }$

IN ORDER TO RATIONALISE, WE USE THE RATIONALISING FACTOR WHICH IS

$( \sqrt{3} + \sqrt{2} )$

WITH THE HELP OF RATIONALISE FACTOR WE MUTLIPLY NUMERATOR AND DENOMINATOR WITH THE RATIONALISING FACTOR.

$\frac{ \sqrt{ 3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} }$

$\frac{( \sqrt{3} + \sqrt{2} }{( \sqrt{3} - \sqrt{2)} } \times \frac{( \sqrt{3} + \sqrt{2} )}{( \sqrt{3} + \sqrt{2} )}$

$\frac{ {( \sqrt{3 + \sqrt{2} )} }^{2} }{( { \sqrt{3} }^{2} - { \sqrt{2} }^{2} }$

OPENING THE IDENTITY HERE

$\frac{3 + 2 + 2 \times \sqrt{3} \times \sqrt{2} }{1}$

$5 + 2 \sqrt{6}$

Step-by-step explanation:

WE USE IDENTITY HERE :

${(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy$

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