3-2√२ upon ३+२√२ factorise
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2
Answer:
(a−
2
b)(a
2
+
2
ab+2b
2
)
(a
3
−b
3
)=a
3
−a
2
b+a
2
b−ab
2
+ab
2
−b
3
=(a
3
−a
2
b)+(a
2
b−ab
2
)+(ab
2
−b
3
)
=a
2
(a−b)+ab(a−b)+b
2
(a−b)
=(a−b)(a
2
+ab+b
2
)
Now, given a
3
−2
2b
3
=(a−
2
b)(a
2
+a(
2
b)+(
2
b)
2
)
=(a−
2
b)(a
2
+
2
ab+2b
2
)
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