Question

3-2√२ upon ३+२√२ factorise​

Answer 1

Answer:

(a−

2

b)(a

2

+

2

ab+2b

2

)

(a

3

−b

3

)=a

3

−a

2

b+a

2

b−ab

2

+ab

2

−b

3

=(a

3

−a

2

b)+(a

2

b−ab

2

)+(ab

2

−b

3

)

=a

2

(a−b)+ab(a−b)+b

2

(a−b)

=(a−b)(a

2

+ab+b

2

)

Now, given a

3

−2

2b

3

=(a−

2

b)(a

2

+a(

2

b)+(

2

b)

2

)

=(a−

2

b)(a

2

+

2

ab+2b

2

)