Question

(-3) - (-2) write it on a number line 7th class integers​

Answer 1

Answer:

first sinplify the question

-3 -(-2)

-3+2= -1

Step-by-step explanation:

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Answer 2

Answer:

⇒  

dx

dy

​  

=  

x−1

y  

2

−2y

​  

 

⇒  

y  

2

−2y

dy

​  

=  

(x−1)

dx

​  

 

⇒∫  

y(y−2)

dy

​  

=  

x−1

dx

​  

 

⇒∫  

y(y−2)

dy

​  

=log(x−1)+c

Let

⇒  

y(y−2)

1

​  

=  

y

A

​  

+  

(y−2)

B

​  

 

⇒1=Ay−2A+By

⇒1+2A

⇒A=  

2

−1

​  

 

and(A+B)y=0,

A+B=0→(i)

PutA=  

2

−1

​  

inequation(i)

2

−1

​  

+B=0,B=  

2

1

​  

 

⇒∫  

y

A

​  

dy+∫  

(y−2)

B

​  

dy=log(x−1)+c

⇒  

2

−1

​  

∫  

y

dy

​  

+  

2

1

​  

∫  

(y−2)

1

​  

=log(x−1+c

⇒  

2

−1

​  

logy+  

2

1

​  

log(y−2)=log(x−2)+logc

⇒  

2

−1

​  

[log(  

y

y−2

​  

)]=log(x−1)c

⇒log  

y

y−2

​  

 

​  

=log(x−1)c

∴  

y

(y−2)

​  

 

​  

=(x−1)c

⇒  

y

y

​  

 

y

−2

​  

=(x−1)  

2

c  

2

 

⇒1−(x−1)  

2

c  

2

=  

y

2

​  

 

∴y=  

−1(x−1)  

2

c  

2

 

2

​  

Ans.

​  

 

Step-by-step explanation: