Question

3(2^x+1) — 2^x+2 + 5 = 0 find x

Answer 1

if y= $2^x$

3(y+1)-4y+5=0
3y+3-4y+5=0
-y=-8
y=8
$2^x$=$2^3$
x=3

Answer 2

Given 3(2^x + 1) - 2^x+2 + 5 = 0

          3 * 2^x + 3 - 2^2 * 2^x + 5 = 0

          3 * 2^x - 4 * 2^x + 5 + 3 = 0

          - 1 * 2^x + 8 = 0

           - 2^x + 8 = 0

             2^x = 8

            2^x = 2^3

              x = 3.


Hope this helps!