(√3+√2)^x+(√3-√2)^x = 10 then what is the value of x?
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Answer:
x=2
Step-by-step explanation:
==: (√3 + √2) ^ x + (√3 - √2) ^ x = 10
Substituting x= 2
==: (√3 +√2) ^ 2 + (√3 - √2) ^ 2
==: (√3) ^ 2 + 2 *√3 *√2 + (√2) ^ 2 + (√3) ^ 2 - 2 * √3 * √2 + (√2) ^ 2
==: 3 + 2 √6 + 2 + 3 – 2√6 + 2
==: 3 + 3 + 2 + 2 = 10
L H.S = R.H.S
==: x=2
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