Question

3. 20% of a first order reaction occurs in 10 minutes. Calculate its tu.
alculate its 1/2
Or​

Answer 1

Answer:

30min

A° = 100

At = 80

Kt = 2.303 log (A°/At)

K = 2.303 Log(5/4)/10

log 5 -.7

log 4 - .6

k = 2.3 × .1/10

t1/2 = 2.3 × 0.3/k

Put Value

t1/2 = 30Min

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