Question

3 - 22 УЗ
2 x x 9х3
Qу 3х3x 2
2 x 27 x2​

Answer 1

Let the three consecutive multiples of 8 be 8x, 8x + 8 and 8x + 16.

As per the conditions, we get

8x + (8x + 8) + (8x + 16) = 888

⇒ 8x + 8x + 8 + 8x + 16 = 888

⇒ 24x + 24 = 888

⇒ 24x = 888 – 24 (transposing 24 to RHS)

⇒ 24x = 864

⇒ x = 864 ÷ 24 (transposing 24 to RHS)