Question

3+23y-8y^2 solve the given factor

Answer 1

3+23y-8y^2=0
8y^2 - 23y - 3 = 0

8y^2 - 24y + y - 3 = 0

8y(y-3) - 1( y- 3) = 0

(8y- 1) (y-3) = 0
8y - 1 = 0. ,y-3 =0

y = 1/8. ,y = 3

Answer 2

Here is your answer

$3 + 23y - 8y {}^{2} = 0 \\ 8y {}^{2} - 23y - 3 = 0 \\ 8y {}^{2} - 24y + y - 3 = 0 \\ 8y(y - 3) + 1(y - 3) = 0 \\ (y - 3)(8y + 1) = 0 \\ y = 3 \: and \: \frac{ - 1}{8}$
Hope it helps you