Math, asked by Sparsh59, 1 year ago

3+23y_8y2 factorise it

Answers

Answered by Asachin49719
1

3 + 23y  - 8 y {2}  = 0 \\ 8y { }^{2}  - 23y - 3 = 0 \\ 8 {y}^{2}  - (24 - 1)y - 3 = 0 \\ 8 {y}^{2}  - 24y + y - 3 = 0 \\8y(y - 3) + 1(y - 3) = 0 \\ (y - 3)(8y + 1) \\ y = 3 \\ y =  - 1 \div 8
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