Physics, asked by akkulgautam14, 13 days ago


3
26. A small block A of mass m, is given a velocity v in
horizontal direction as shown. The bigger block B is
initially at rest. The curved surface of the block B
becomes vertical at the top point. If M = 4mo, what
should be the minimum value of v so that the block
A climbs upto the top on B? All surfaces are
smooth (g = 10 m/s2)
2
ng ty 4 m
3
А
M M
mo. (mfM) gh,
no (Moringademis
(2) 10 m/s
(3) 9 m/s
(4) 2 m/s​

Answers

Answered by mithuanushtha
3

Answer:

A small block of mass m which is started with a velocity V on the horizontal part of the biger block of mass M placed on a horizontal floor. <br> Since the small body of mass mis started with a velocity V in the horizontal edirection, so the total initial momentum at tehinitil position in the horizontl bigger block in From L.C.K m. <br>

<br>

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