3^27÷3^14=3^2x . find value of x
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Answered by
3
3^27/3^14 = 3^2x
( a^m/a^n = a^m-n)
3^27-14 = 3^2x
3^13 = 3^2x
(compare)
13 = 2x
x = 13/2
value of x is 13/2
( a^m/a^n = a^m-n)
3^27-14 = 3^2x
3^13 = 3^2x
(compare)
13 = 2x
x = 13/2
value of x is 13/2
Answered by
16
Heya friend,
Here is the answer you were looking for:
![{3}^{27} \div {3}^{14} = {3}^{2x} \\ {3}^{27} \div {3}^{14} = {3}^{2x} \\](https://tex.z-dn.net/?f=+%7B3%7D%5E%7B27%7D++%5Cdiv++%7B3%7D%5E%7B14%7D++%3D++%7B3%7D%5E%7B2x%7D++%5C%5C+)
We know that
![{a}^{m} \div {a}^{n} = {a}^{m - n} {a}^{m} \div {a}^{n} = {a}^{m - n}](https://tex.z-dn.net/?f=+%7Ba%7D%5E%7Bm%7D++%5Cdiv++%7Ba%7D%5E%7Bn%7D++%3D++%7Ba%7D%5E%7Bm+-+n%7D+)
So,
![{3}^{27 - 14} = {3}^{2x} \\ {3}^{27 - 14} = {3}^{2x} \\](https://tex.z-dn.net/?f=+%7B3%7D%5E%7B27+-+14%7D++%3D++%7B3%7D%5E%7B2x%7D++%5C%5C+)
As the bases are same, so putting the powers equal
![27 - 14 = 2x \\ \\ 13 = 2x \\ \\ \frac{13}{2} = x \\ \\ x = 6.5 27 - 14 = 2x \\ \\ 13 = 2x \\ \\ \frac{13}{2} = x \\ \\ x = 6.5](https://tex.z-dn.net/?f=27+-+14+%3D+2x+%5C%5C++%5C%5C+13+%3D+2x+%5C%5C++%5C%5C++%5Cfrac%7B13%7D%7B2%7D++%3D+x+%5C%5C++%5C%5C+x+%3D+6.5)
Hope this helps!!!
Regards : Mahak24
Thanks...
☺☺
Here is the answer you were looking for:
We know that
So,
As the bases are same, so putting the powers equal
Hope this helps!!!
Regards : Mahak24
Thanks...
☺☺
DaIncredible:
thanks for brainliest ^-^
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