3÷2a²b 1÷2 - ab
and 3a²b + 2ab
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Answer:
(2ab²+3a²b-4ab) - (3ab-8ab²+2a²b) = ab( 10b + a - 7)
Step-by-step explanation:
2ab²+3a²b-4ab ; 3ab-8ab²+2a²b Subtract the second polynomial from the first.
2ab²+3a²b-4ab
3ab-8ab²+2a²b
(2ab²+3a²b-4ab) - (3ab-8ab²+2a²b)
= 2ab²+3a²b-4ab -3ab + 8ab² - 2a²b
= 2ab² + 8ab² + 3a²b - - 2a²b - 4ab - 3ab
= 10ab² + a²b - 7ab
= ab( 10b + a - 7)
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