3.2g of oxygen and 0.2g of hydrogen are placed in a 1.12 liter flask at 0 degree centigrade.the total pressure of the gas mixture will be
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Answered by
96
Moles of oxygen = 3.2 g / (32 g/mol) = 0.1 mol
Moles of hydrogen = 0.2 g / (2 g/mol) = 0.1 mol
Total moles = n = 0.1 + 0.1 = 0.2 mol
P = nRT/V
= (0.2 × 0.0821 × 273) / 1.12
= 4 Pa
Total pressure of gaseous mixture is 4 Pa
Moles of hydrogen = 0.2 g / (2 g/mol) = 0.1 mol
Total moles = n = 0.1 + 0.1 = 0.2 mol
P = nRT/V
= (0.2 × 0.0821 × 273) / 1.12
= 4 Pa
Total pressure of gaseous mixture is 4 Pa
Answered by
5
Answer:4 atm
Explanation:
By using simply idge and adding the no of moles
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