Question

3+2i/2-3i+3-2i/2+3i express it in the form of a+ib

Answer 1

Answer:

Step-by-step explanation:

we have x=(√2 + √3i) + (√2 - √3i) / (√3 + √2i ) + (√3 - √2i )

            =(√2 + √3i+ √2 - √3i) / (√3 + √2i  + √3 - √2i )

         =2√2 / 2√3

       = √2/√3

because the imaginary part here is zero

so  if we express it in a+ib then

 a+ib = (√2/√3) + 0i