Question

3+2i/2-5i + 3-2i/2+5i​

Answer 1

Step-by-step explanation:

$\frac{3 + 2i}{2 - 5i} + \frac{3 - 2i}{2 + 5i} \\ \frac{(2 + 5i)(3 + 2i) + (3 - 2i)(2 - 5i)}{ ({2}) ^{2} - ({5i})^{2} } \\ \frac{6 + 19i + 10 {i}^{2} + 6 - 19i + 10 {i}^{2} }{4 + 25 } \\ we \: know \: that \: {i}^{2} = - 1 \\ \frac{12 - 10 - 10}{29} \\ \frac{ - 8}{29}$