Question

3+2i
____
-2+i
state value of a and bi​

Answer 1

Step-by-step explanation:

3

$\frac{ 3 + 2i}{ - 2 + i} \times \: \frac{2 + i}{2 + i} \\ \frac{(3 + 2i)(2 + i)}{( - 2 + i)(2 + i)} \\ \frac{(6 + 3i + 4i + 2 {i}^{2})}{( { - 2}^{2} - {i}^{2}) } \\ \frac{(6 + 7i + 2( - 1))}{4 - ( - 1)} \\ \frac{6 + 7i - 2 }{4 + 1} \\ \frac{4 + 7i}{5} \\ \frac{4}{5} + \frac{7i}{5}$

A=

$\frac{4}{5}$

Bi=

$\frac{7i}{5}$

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