Math, asked by ShreyaShruti, 1 year ago

(3+2i) (3-2i) in form of a+ib

Answers

Answered by amitnrw
2

Answer:


Step-by-step explanation:

(3+2i)/(3-2i)

multiply and divide by 3+2i

((3+2i)^2)/(9-4i^2)

(9 + 4i^2 + 12i)/(9+4)

as i^2 = -1

(9 -4 + 12i )/13

(5+12i)/13

5/13 +( 12/13)i

a = 5/13

b = 12/13


amitnrw: Please mark as brainliest if it helped
Answered by adithyaramapuram29
1

Answer:13+0i


Step-by-step explanation:

(3+2i)(3-2i)

= 9-4i^2

=9+4

=13+0i

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