(3+2i) (3-2i) in form of a+ib
Answers
Answered by
2
Answer:
Step-by-step explanation:
(3+2i)/(3-2i)
multiply and divide by 3+2i
((3+2i)^2)/(9-4i^2)
(9 + 4i^2 + 12i)/(9+4)
as i^2 = -1
(9 -4 + 12i )/13
(5+12i)/13
5/13 +( 12/13)i
a = 5/13
b = 12/13
amitnrw:
Please mark as brainliest if it helped
Answered by
1
Answer:13+0i
Step-by-step explanation:
(3+2i)(3-2i)
= 9-4i^2
=9+4
=13+0i
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