(3-2i)(4+3i)/3+i how to solve this problem
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(3-2i)(4+3i)/3+i
= 3(4+3i)-2i(4+3i)/3+i
= (12+9i-6i-6i²)/3+i
= (12+3i-6i²)/3+i
= 33-24i ans.
= 3(4+3i)-2i(4+3i)/3+i
= (12+9i-6i-6i²)/3+i
= (12+3i-6i²)/3+i
= 33-24i ans.
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