Physics, asked by sriramthegreat2002, 11 months ago

3(-2i+j- 3k) +2(5i +3–2k)

Answers

Answered by Anonymous

4

3(-2i + j -3k) + 2(5i + 3- 2k)

-6i + 3j - 9,k + 10i + 6 -4k

4i + 3j - 13k + 6

Answered by shruti6796

1

Answer:

4i+3j-13k

Explanation:

-6i+3j-9k

+10i+6j-4k

(-6i+10i)+(3j+6j)+(-9k-4k)

=4i+3j-13k

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