Math, asked by syedabrarhussain6550, 1 month ago

(3-2i)(x-yi)=2(x-2yi)+4i-1​

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Answered by happyaswal101
1

Step-by-step explanation:

(x+iy)(2−3i)=4+i

(x+iy)(2−3i)=4+i2x−(3x)i+(2y)i−3yi square =4+i

2x+3y + (2y−3x) i=4+i

(2y−3x) i=4+iComparing the real & imaginary parts,

(2y−3x) i=4+iComparing the real & imaginary parts,2x+3y=4--------------------------(1)

(2y−3x) i=4+iComparing the real & imaginary parts,2x+3y=4--------------------------(1)2y−3x=1----------------------------(2)

(2y−3x) i=4+iComparing the real & imaginary parts,2x+3y=4--------------------------(1)2y−3x=1----------------------------(2)Solving eq(1) & eq(2),

(2y−3x) i=4+iComparing the real & imaginary parts,2x+3y=4--------------------------(1)2y−3x=1----------------------------(2)Solving eq(1) & eq(2),4x+6y=8

(2y−3x) i=4+iComparing the real & imaginary parts,2x+3y=4--------------------------(1)2y−3x=1----------------------------(2)Solving eq(1) & eq(2),4x+6y=8−9x+6y=3

(2y−3x) i=4+iComparing the real & imaginary parts,2x+3y=4--------------------------(1)2y−3x=1----------------------------(2)Solving eq(1) & eq(2),4x+6y=8−9x+6y=313x=5⇒x= 5/13

13 y= 14/13

∴(x,y)=( 5/13 , 14/13)

Answered by namiteshmeshram662
0

Answer:

this is your answer ok bye bye

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