Question

3(2k+1)-2(k-5)-5(-5-2k)=16

Answer 1

Answer: -1.2743

Step-by-step explanation:6k+3-2k+5+25+10k=16

group the like terms together

6k-2k+10k+3+5+25=16

solve

14k+33=16

14k=16-33

14k=-17

k=-17÷14

k=-1.2743

Answer 2

Given,

$\[3\left( {2k + 1} \right) - 2\left( {k - 5} \right) - 5\left( { - 5 - 2k} \right) = 16\]$

Solution,

$\[\begin{array}{l}3\left( {2k + 1} \right) - 2\left( {k - 5} \right) - 5\left( { - 5 - 2k} \right) = 16\\ \Rightarrow 6k + 3 - 2k + 10 + 25 + 10k = 16\\ \Rightarrow 38 + 14k = 16\\ \Rightarrow 14k = - 22\\ \Rightarrow 7k = - 11\end{array}\]$

$\[ \Rightarrow k = \frac{{ - 11}}{7}\]$

Hence the value of k is $\[\frac{{ - 11}}{7}\]$