(3)^2n×(3)^n=(3)^12 find the value of n
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4
Step-by-step explanation:
use the identity: a^nxa^m = a^n+m
this gives,
3^2n+n 3^12
3^3n = 3^12
now as bases are same so you can compare the powers.
3n=12
n= 12/3
n=4
ans=n=4
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