(3/2p²+ 2/3q²) (2p²- 3q²)
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Answer:
=6/2p^4-6/3q^4-19/6p^2q^2
Step-by-step explanation:
(3/2p^2+2/3q^2) (2p^2-3q^2)
=3/2p^2(2p^2-3q^2) + 2/3q^2(2p^2-3q^2)
=6/2p^4-9/2p^2q^2 +4/3q^2p^2-6/3q^4
=6/2p^4-6/3q^4(-9/2p^2q^2 +4/3q^2p^2)
=6/2p^4-6/3q^4-19/6p^2q^2
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