Math, asked by debjanid6066, 2 months ago

3(2p2-q-q2r+r2s)+4(r2s+q2r+p2q

Answers

Answered by CommanderBrainly

11

Step-by-step explanation:

$\bigstar{\underline{\underline{{\sf\ \red{ Solution:-}}}}}$

${6p}^{2} - 3p + {q}^{2} r + {7r}^{2} s + {4p}^{2} q$

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