Question

3/2root3-1
urgent
plzzz

Answer 1

$\bold{\boxed{Solution:}}$


$\frac{3}{2 \sqrt{3} - 1} \\ \\ \frac{3}{2 \sqrt{3} - 1} \times \frac{2 \sqrt{3} + 1 }{2 \sqrt{3} + 1 } \\ \\ \frac{2(2 \sqrt{3} + 1)}{(2 \sqrt{3}) {}^{2} - (1) {}^{2} } \\ \\ \frac{4 \sqrt{3} + 2}{12 - 1} \\ \\ \frac{2(2 \sqrt{3} + 1)}{11}$

$\bold{\boxed{Thank \:you :))}}$

Answer 2

Answer:

$\frac{3}{2 \sqrt{3} - 1} \\ \\ \frac{3}{2 \sqrt{3} - 1} \times \frac{2 \sqrt{3} + 1 }{2 \sqrt{3} + 1} \\ \\ \frac{3(2 \sqrt{3} + 1)}{(2 \sqrt{3} ) {}^{2} - (1) { }^{2} } \\ \\ \frac{6 \sqrt{3} + 3}{12 - 1} \\ \\ \frac{2(3 \sqrt{3} + 1)}{11}$

Thank you :)