Question

(3/2x+1)³
write in expanded form​

Answer 1

Step-by-step explanation:

$(x + y)^{3} = {x}^{3} + {y}^3 + 3xy(x + y)$

So

${(\frac{3}{2x + 1})}^{3} = > \frac{ {3}^{3} }{ {(2x)}^{3} + 1 + 3(2x)(2x + 1)} = >$

$\frac{27}{8 {x}^3 + 1 + 6x(2x + 1)} = > \frac{27}{8 {x}^{3} + 1 + 12 {x}^{2} + 6x}$

Hope it helps you.

Answer 2

Answer:

Step-by-step explanation: