Question

3^2x+1÷9=27 find the value of x

Answer 1

Answer:

${3}^{2x} + \frac{1}{9} = 27 \\ \\ {3}^{2x} + {3}^{ - 2} = {3}^{3} \\ \\ they \: have \: same \: base \\ \\ 2x - 2 = 3 \\ \\ 2x = 5 \\ \\ x = \frac{5}{2} \\ \\ x = 2.5$