Question

3^2x^2-2.3x^2+x+6+3^[x+6]=0

Answer 1

Answer:

(3^x^2)^2–2•3^x^2•3^(x+6)+3^2(x+6)=0

Let 3^x^2=Y

Now,y^2–2•3^(x+6)•y+3^2(x+6)=0

y^2–2•3^(x+6)•y+{3^(x+6)}^2=0

{Y-3^(x+6)}^2=0

Y-3^(x+6)=0

3^x^2-3^(x+6)=0

3^x(3^(x^2-x)-3^6)=0

3^(x^2-x)-3^6=0

3^(x^2-x)=3^6

X^2-X-6=0

X=3,-2

Answer 2

SOLUTION

Refer to the attachment

hope it helps ☺️