3/2x + 2/3y = 5 , 5/x - 3/y = 1
Solve by Elemination method....
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Answered by
4
Answer:
x = 1/2 , y = 1/3
Solution:
Here ,
The given equations are ;
3/2x + 2/3y = 5 -------(1)
5/x - 3/y = 1 ------(2)
Eq-(1) can be rewritten as ;
=> 3/2x + 2/3y = 5
=> (9y + 4x)/6xy = 5
=> (9y + 4x)/xy = 5•6
=> 9/y + 4/x = 30 ---------(3)
Now,
Multiplying eq-(2) by 4 , we get ;
=> 4•(5/x - 3/y) = 1•4
=> 20/x - 12y = 4 -------(4)
Now,
Multiplying eq-(3) by 3 , we get ;
=> 3•(9/y + 4/x) = 30•3
=> 27/y + 12/x = 90 --------(5)
Now,
Adding eq-(4) and (5) , we get ;
=> 20/x - 12/y + 27/x + 12/y = 4 + 90
=> 20/x + 27/x = 94
=> 47/x = 94
=> x = 47/94
=> x = 1/2
Now,
Putting x = 1/2 in eq-(2) , we get ;
=> 5/x - 3/y = 1
=> 5/(1/2) - 3/y = 1
=> 5×2 - 3/y = 1
=> 10 - 3/y = 1
=> - 3/y = 1 - 10
=> -3/y = -9
=> y = -3/-9
=> y = 1/3
Hence ,
x = 1/2 , y = 1/3
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0
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