Math, asked by Parithosh07, 10 months ago

3/2x + 2/3y = 5 , 5/x - 3/y = 1​
Solve by Elemination method....
Answer only if you know it correctly...​​​

Answers

Answered by AlluringNightingale
4

Answer:

x = 1/2 , y = 1/3

Solution:

Here ,

The given equations are ;

3/2x + 2/3y = 5 -------(1)

5/x - 3/y = 1 ------(2)

Eq-(1) can be rewritten as ;

=> 3/2x + 2/3y = 5

=> (9y + 4x)/6xy = 5

=> (9y + 4x)/xy = 5•6

=> 9/y + 4/x = 30 ---------(3)

Now,

Multiplying eq-(2) by 4 , we get ;

=> 4•(5/x - 3/y) = 1•4

=> 20/x - 12y = 4 -------(4)

Now,

Multiplying eq-(3) by 3 , we get ;

=> 3•(9/y + 4/x) = 30•3

=> 27/y + 12/x = 90 --------(5)

Now,

Adding eq-(4) and (5) , we get ;

=> 20/x - 12/y + 27/x + 12/y = 4 + 90

=> 20/x + 27/x = 94

=> 47/x = 94

=> x = 47/94

=> x = 1/2

Now,

Putting x = 1/2 in eq-(2) , we get ;

=> 5/x - 3/y = 1

=> 5/(1/2) - 3/y = 1

=> 5×2 - 3/y = 1

=> 10 - 3/y = 1

=> - 3/y = 1 - 10

=> -3/y = -9

=> y = -3/-9

=> y = 1/3

Hence ,

x = 1/2 , y = 1/3

Answered by wwwseenalingampalli
0

Answer:

hope it is helpful to you.

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